Webb13 juli 2006 · So the total number of 3 digit integers >= 700 where 2 of the digits are the same and the 3rd digit different = 3* (3*9*1) = 81 This set of 81 integers also hold the integer 700. But since we're only looking for integers > 700, we need to remove 1 from 81, to give us 80 integers. Quote Reply to this topic... All Activity Home WebbOf the three-digit integers greater than 700, how many have two digits that are equal to each other and the remaining digit different from the other two? (a) 82 (b) 36 (c) 80 (d) 90. ... None of these a prime number greater than 97, then the largest integer that divides F(p) for all values of p is: 26. If n is a positive integer, then n(n + 1) ...
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Webb25 jan. 2024 · Find the sum of the most significant three-digit number and the smallest three-digit number. Ans: We know that, The greatest three-digit number is \ (999\). The smallest three-digit number is \ (100\). So, we need to add these two numbers. Now, \ (999+100\) \ (=1099\) Hence, the required answer is \ (1099\). Q.2. Webb20 feb. 2024 · 1. It is a 3 digit number > 700 (or between 701-999, inclusive). 2. All digits are different and NON ZERO. 3. The numbers must be ODD --> the last digit can be 1 of 1,3,5,7,9 Based on this, the numbers can be of the following 3 types: Type 1: 7AB Type 2: 8EF Type 3: 9CD For type 1 and type 3, be very careful that the digits must be different. farhan sheikh greenwich
Of the three - digit integers greater than 700 , how many …
WebbConsider all positive integers with 3 different digits. (Note that 0 cannot be the first digit.) (1) How many are greater than 700? (ii) How many are dd? (iii) How many are even? (iv) How many are divisible by 5? Question thumb_up 100% Transcribed Image Text: Consider all positive integers with 3 different digits. WebbSOLUTION: Consider all positive integers with three different digits. (Note that zero cannot be the first digit.) Find the number of them which are: (a) greater than 700; (b) odd; (c) divi Algebra: Combinatorics and Permutations Solvers Lessons Answers archive Click here to see ALL problems on Permutations WebbOf the three-digit integers greater than 700, how many have two digits that are equal to each other and the remaining digit different from the other two? (A) 90 (B) 82 (C) 80 (D) 45 (E) 36. Correct Answer: C. Full explanation coming soon. Send us a note if you’d like this added to the express queue! farhan saeed upcoming movie