WebOct 10, 2005 · Upon evisceration, it was discovered that the frog had died due to acid ingestion. 10mL of gastric juice was found in its stomach required 7.2mL of 0.1 M NaOh for neutralization. Calculate the pH of its gastric juice. I'm confused, how would I approach this problem. Well first you might want to find the pH of the NaOH solution. WebAt this temperature, then, neutral solutions exhibit pH = pOH = 6.31, acidic solutions exhibit pH less than 6.31 and pOH greater than 6.31, whereas basic solutions exhibit pH greater than 6.31 and pOH less than 6.31. ... Calculation of pH from [H 3 O +] What is the pH of stomach acid, a solution of HCl with a hydronium ion concentration of 1.2 ...
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WebThe pH of the gastric contents determines whether some substances are absorbed. At a low pH, for example, the environment is acidic and aspirin is absorbed from the stomach almost as rapidly as water, but, as the pH of the stomach rises and the environment becomes more basic, aspirin is absorbed more slowly. WebThe pH scale is often said to range from 0 to 14, and most solutions do fall within this range, although it’s possible to get a pH below 0 or above 14. Anything below 7.0 is acidic, and anything above 7.0 is alkaline, or basic. photography weaving
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WebMay 22, 2024 · The pH level of blood reflects how acidic it is. The body maintains blood pH using a number of processes. ... stomach upset or feeling sick; muscle seizures or weakness; unconsciousness and coma ... WebAcidity is measured on a pH scale. This scale goes from 0 to 14. The lower the pH level, the stronger the acidity level of the liquid. For example, the least acidic fluids are at 14 and are called alkaline fluids. In the middle, at 7.0, are the neutral fluids, such as pure water. Stomach acid has a pH between 1 and 2.. WebAt 25 °C, the value of Kw is 1.0 × 10 − 14, and so: 14.00 = pH + pOH The hydronium ion molarity in pure water (or any neutral solution) is 1.0 × 10 − 7 M at 25 °C. The pH and pOH of a neutral solution at this temperature are therefore: pH = − log[H3O +] = − log(1.0 × 10 − 7) = 7.00 pOH = − log[OH −] = − log(1.0 × 10 − 7) = 7.00 photography website project in php